To determine the enthalpy change during interaction (Hydrogen Bond formation) between acetone and chloroform.
Requirements:
A 250 ml thermos flask with two holes, thermometer, beakers, measuring cylinder, etc.
Chemical Required
Acetone (100ml) and Chloroform (100 ml)
Theory:
Procedure:
- Put 100ml acetone in a thermos flask. Note its temp.
- Put 100ml chloroform in a beaker and note its temperature
- The temp. of chloroform and acetone should be the same.
- Add the chloroform into the beaker containing acetone.
- Stir the mixture and note the constant tempature of the mixture.
Observations and Calculations:-
Initial temperature of acetone and chloroform=t 1°C
Final temperature of liquid mixture=t ₂°
Rise in tempature = (t ₂ -t 1 )°C
Volume of chloroform taken = 100ml.
Specific heat of choroform-2.18 J/g (S₁)
Specific heat of acetone = 0.96 J/g (S₂)
Water Equivalent of calorimeter = w gram
The volume of acetone taken 100ml,
Density of chloroform =1.499 g/ml
Density of acetone = 0.787 g/ml
Heat evolved on heating acetone and chloroform =
= Heat gained by beaker + Heat gained by chloroform
+ Heat gained by acetone
=w × 4.2 × (t₂-t₁) + 100 × 1.499 × 2.18 × (t₂-t₁) +100 × 787 × 0.96 × (t₂-t₁)
= [ w × 4.2 + 100 × 1.499 × 2.18+100 × 787×96] (t₂-t₁)
= ________ Joules.
.
Precautions:-
Chloroform and acetone should be transferred immediately after measuring as these are volatile.
Result
Enthalpy change during mixing of 100ml of acetone with 100 ml of chloroform = - x Joules.
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